A) \[9.02\times {{10}^{5}}N/{{m}^{2}}\]
B) \[0.02\times {{10}^{4}}N/{{m}^{2}}\]
C) \[9.02\times {{10}^{3}}N/{{m}^{2}}\]
D) \[9.02\times {{10}^{6}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
\[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}=\sqrt{\frac{3p}{\rho }}\] \[p=\frac{V_{rms}^{2}\rho }{3}\] \[=\frac{{{(1840)}^{2}}\times (0.8)}{3}\] \[=9.02\times {{10}^{5}}N/{{m}^{2}}\]
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