A) \[2N{{O}_{2}}(g){{N}_{2}}{{O}_{4}}(g)\]
B) \[2HI(g){{H}_{2}}(g)+{{I}_{2}}(g)\]
C) \[2{{O}_{3}}(g)3{{O}_{2}}(g)\]
D) \[PC{{l}_{5}}(g)PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
Correct Answer: B
Solution :
\[2HI(g){{H}_{2}}(g)+{{I}_{2}}(g)\] At equilibrium, number of moles of reactant and products are same ie,\[\Delta n=0,\]Hence, in this reaction change in pressure does not affect the equilibrium.
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