RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The formula of wavelength of spectral lines for hydrogen atom is

    A)  \[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\]

    B)  \[\frac{1}{\lambda }=R\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)\]

    C)  \[\frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{1}}}-\frac{1}{{{n}_{2}}} \right)}^{2}}\]

    D)  \[\frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{2}}}-\frac{1}{{{n}_{1}}} \right)}^{2}}\]

    Correct Answer: A

    Solution :

     Wavelength of spectral lines for hydrogen atom is \[\frac{1}{\lambda }=\overline{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] where R is Rydberg constant.


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