RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The geometric mean of the roots of the equation\[{{x}^{2}}-18x+9=0\]is

    A)  \[9\sqrt{2}\]

    B)  \[9\]

    C)  \[\frac{1}{81}\]

    D)  \[\frac{1}{77}\]

    Correct Answer: C

    Solution :

     \[{{x}^{2}}-18x+9=0\] Let roots are\[\alpha \]and\[\beta ,\]then \[\alpha +\beta =18\] and             \[\alpha \beta =9\] \[\therefore \]Geometric and mean \[=\sqrt{\alpha \beta }\] \[=\sqrt{9}\] \[=3\]


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