A) \[\frac{1}{x\sqrt{1-{{x}^{2}}}}\]
B) \[\frac{1}{x\sqrt{1+x}}\]
C) \[\frac{1}{x\sqrt{{{x}^{2}}-1}}\]
D) \[\frac{1}{x\sqrt{x-1}}\]
Correct Answer: C
Solution :
\[\frac{d}{dx}({{\sec }^{-1}}x)=\frac{1}{x\sqrt{{{x}^{2}}-1}}\]
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