A) \[\frac{1}{2}\log \frac{x-1}{x+1}+c\]
B) \[\log \frac{x-1}{x+1}+c\]
C) \[\frac{1}{2}\log \frac{x+1}{x-1}+c\]
D) \[\log \frac{x+1}{x-1}+c\]
Correct Answer: B
Solution :
\[\int{\frac{2dx}{{{x}^{2}}-1}}=2\left[ \frac{1}{2}\log \left( \frac{x-1}{x+1} \right) \right]+c\] \[=\log \left( \frac{x-1}{x1} \right)+c\]
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