RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    If amplification factor and mutual conductance are 20 and\[{{10}^{-3}}\]mho respectively, then plate resistance will be

    A)  20 k\[\Omega \]           

    B) \[10\,k\Omega \]

    C)  \[20\times {{10}^{-3}}\Omega \]       

    D)  None of these

    Correct Answer: A

    Solution :

     \[\mu ={{g}_{m}}\times {{r}_{p}}\] \[{{r}_{p}}=\frac{\mu }{{{g}_{m}}}=\frac{20}{{{10}^{-3}}}=2\times {{10}^{4}}\Omega =20\,k\Omega \]


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