RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    Three capacitors of equal capacitances 3 \[\mu \]F each are connected in a circuit. Then their maximum and minimum capacities will be

    A)  \[9\mu F,1\mu F\]          

    B)  \[8\mu F,2\mu F\]

    C)  \[9\mu F,0\mu F\]          

    D)  \[3\mu F,2\mu F\]

    Correct Answer: A

    Solution :

     In series, \[\frac{1}{{{C}_{s}}}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\] \[{{C}_{s}}=1\,\mu F\] In parallel \[{{C}_{p}}=3+3+3=9\mu F\]


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