A) \[-3,+3\]
B) \[-1,+1\]
C) \[+1,-1\]
D) \[-3,+5\]
Correct Answer: D
Solution :
\[N{{H}_{4}}N{{O}_{3}}NH_{4}^{+}+NO_{3}^{-}\] Let the oxidation number of N is\[x\]. In \[NH_{4}^{+}\] \[x+4=1\] \[x=1-4=-3\] In \[NO_{3}^{-}\] \[x+3(-2)=-1\] \[x-6=-1\] \[x=-1+6\] \[=+5\] Hence, the set of oxidation number of nitrogen in ammonium nitrate is\[-3,+5\].
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