RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The formula of wavelength of spectral lines for hydrogen atom is

    A)  \[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\]

    B)  \[\frac{1}{\lambda }=R\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)\]

    C)  \[\frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{1}}}-\frac{1}{{{n}_{2}}} \right)}^{2}}\]

    D)  \[\frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{2}}}-\frac{1}{{{n}_{1}}} \right)}^{2}}\]

    Correct Answer: A

    Solution :

     Formula of spectral lines wavelength for hydrogen atom is as \[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] where, R = Rydberg's constant


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