RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    \[{{\left( \frac{1+\sin \theta +i\cos \theta }{1+\sin \theta -i\cos \theta } \right)}^{n}}\]is equal to

    A)  \[\cos n\left( \frac{\pi }{2}-\theta  \right)+i\sin n\left( \frac{\pi }{2}-\theta  \right)\]

    B)  \[\cos n\left( \frac{\pi }{2}-\theta  \right)-i\sin n\left( \frac{\pi }{2}-\theta  \right)\]

    C)  \[\cos n\theta +i\sin n\theta \]

    D)  \[\sin n\theta +i\cos n\theta \]

    Correct Answer: A

    Solution :

     \[{{\left( \frac{1+\sin \theta +i\cos \theta }{1+\sin \theta -i\cos \theta } \right)}^{n}}\] \[={{\left[ \frac{1+\cos \left( \frac{\pi }{2}-\theta  \right)+i\sin \left( \frac{\pi }{2}-\theta  \right)}{1+\cos \left( \frac{\pi }{2}-\theta  \right)-i\sin \left( \frac{\pi }{2}-\theta  \right)} \right]}^{n}}\] \[={{\left[ \frac{\begin{align}   & 1+2{{\cos }^{2}}\frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)-1+i2\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,.\cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \\ \end{align}}{\begin{align}   & 1+2{{\cos }^{2}}\frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)-1-i2\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,.\cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \\ \end{align}} \right]}^{n}}\] \[={{\left[ \frac{2\cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)\left\{ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)+i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right\}}{2\cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)\left\{ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)-i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right\}} \right]}^{n}}\]\[={{\left\{ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)+i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right\}}^{n}}\]       \[{{\left\{ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)-i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right\}}^{-n}}\] \[={{\left[ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)+i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right]}^{n}}\]             \[{{\left[ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)+i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right]}^{n}}\] \[={{\left[ \cos \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right)+i\sin \frac{1}{2}\left( \frac{\pi }{2}-\theta  \right) \right]}^{2n}}\] \[=\cos n\left( \frac{\pi }{2}-\theta  \right)+i\sin n\left( \frac{\pi }{2}-\theta  \right)\]


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