RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    If\[A=\left[ \begin{matrix}    0 & 1  \\    0 & 0  \\ \end{matrix} \right],a,b\]are arbitrary scalars and\[I\]is an unit matrix of order\[2\times 2,\]then\[{{(aI+bA)}^{2}}\]is equal to

    A)  \[{{a}^{2}}I+{{b}^{2}}{{A}^{2}}\]

    B)  \[{{a}^{2}}I+2abA\]

    C)  \[{{a}^{2}}I+2abA+{{b}^{2}}\]

    D)  \[{{a}^{2}}I+{{b}^{2}}A\]

    Correct Answer: B

    Solution :

     \[A=\left[ \begin{matrix}    0 & 1  \\    0 & 0  \\ \end{matrix} \right],{{A}^{2}}=\left[ \begin{matrix}    0 & 1  \\    0 & 0  \\ \end{matrix} \right]\left[ \begin{matrix}    0 & 1  \\    0 & 0  \\ \end{matrix} \right]=\left[ \begin{matrix}    0 & 0  \\    0 & 0  \\ \end{matrix} \right]\] \[\therefore \] \[{{(aI+bA)}^{2}}={{a}^{2}}I+2abA\]


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