A) \[\log \{x+\sqrt{{{x}^{2}}+1}\}\]
B) \[\log \{x+\sqrt{{{x}^{2}}-1}\}\]
C) \[\frac{1}{2}\log \{x+\sqrt{{{x}^{2}}+1}\}\]
D) \[\frac{1}{2}\log \{x+\sqrt{{{x}^{2}}-1}\}\]
Correct Answer: B
Solution :
\[{{\cosh }^{-1}}x=log\{x+\sqrt{{{x}^{2}}-1}\}\]
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