A) \[x\]
B) \[\frac{1}{x}\]
C) \[-x\]
D) \[-\frac{1}{x}\]
Correct Answer: D
Solution :
\[f[f(x)]=f\left[ \frac{1+x}{1-x} \right]\] \[=\frac{1+\frac{1+x}{1-x}}{1-\frac{1+x}{1-x}}\] \[=\frac{1-x+1+x}{1-x-1-x}=\frac{2}{-2x}=-\frac{1}{x}\]You need to login to perform this action.
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