RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    In adiabatic process, the work done by system is 50 J, then

    A)  the temperature of the system will be increase 50 J

    B)  the temperature of the system will be constant

    C)  the internal energy of the system will be increase 50 J

    D)  the internal energy of the system will be decrease 50 J

    Correct Answer: D

    Solution :

     From first law of thermodynamic \[dQ=dU+dW\] For adiabatic process \[dQ=0\] \[\therefore \] \[dU+dW=0\] \[dU=-50J\] Therefore, the internal energy of system will decrease.


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