A) 2/3
B) 4/9
C) 1/4
D) 16/81
Correct Answer: A
Solution :
\[{{r}_{n}}=\sqrt{bn\lambda }\] \[{{D}_{n}}=2\sqrt{bn\lambda }\] \[\therefore \] \[\frac{{{D}_{4}}}{{{D}_{9}}}=\sqrt{\frac{4}{9}}=\frac{2}{3}\]
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