A) \[\frac{2M}{\pi }\]
B) \[\frac{M}{\pi }\]
C) \[M\]
D) \[M\pi \]
Correct Answer: A
Solution :
\[M=m\times L\] In semicircle \[L=\pi r\] \[M'=m\times d\] \[=m\times \frac{2L}{\pi }\] \[=\frac{2M}{\pi }\]
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