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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    In a circuit the current is given by\[I={{l}_{0}}sin\] \[(\omega t-\pi /2)\]and the potential is\[V={{V}_{0}}sin\] at, then

    A)  \[\frac{1}{2}{{I}_{0}}{{e}_{0}}\,watt\]

    B)  \[{{I}_{0}}{{\varepsilon }_{0}}\,watt\]

    C)  \[{{I}_{0}}\,watt\]

    D)  \[zero\]

    Correct Answer: D

    Solution :

     \[{{P}_{av}}={{V}_{rms}}{{I}_{rms}}\cos \phi \] \[=\frac{{{V}_{0}}}{\sqrt{2}}\times \frac{{{I}_{0}}}{\sqrt{2}}\cos \frac{\pi }{2}\] \[{{P}_{av}}=0\]


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