A) \[C{{H}_{3}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}C{{H}_{2}}COOH\]
C) \[C{{H}_{3}}COC{{H}_{3}}\]
D) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
Correct Answer: C
Solution :
\[\underset{propyne}{\mathop{C{{H}_{3}}}}\,-C\equiv CH+{{H}_{2}}O\xrightarrow[{}]{{{H}^{+}}/H{{g}^{2+}}}\] \[\underset{enolic\text{ }form\text{ }of\text{ }acetone}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,\equiv C{{H}_{2}}}}\,\underset{acetone}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,\equiv C{{H}_{3}}}}\,\]
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