A) \[x-y+1=0\]
B) \[x+y+1=0\]
C) \[x+y-1=0\]
D) \[x-y-1=0\]
Correct Answer: A
Solution :
Equation of tangent at (1, 2) is \[2y=2(x+1)\] \[[\because y{{y}_{1}}=2(x+{{x}_{1}})]\] \[\Rightarrow \] \[y=x+1\] \[\Rightarrow \] \[x-y+1=0\]
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