A) \[\frac{5}{36}\]
B) \[\frac{1}{6}\]
C) \[\frac{7}{36}\]
D) \[\frac{8}{36}\]
Correct Answer: B
Solution :
The number of ways of getting the sum seven \[=\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}\] Total number of ways\[=6\times 6=36\] \[\therefore \]Required probability \[=\frac{6}{36}=\frac{1}{6}\]
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