A) 13.6 eV
B) 59.60 eV
C) 15 keV
D) less from 1 eV
Correct Answer: D
Solution :
The average kinetic energy of molecules of gas at temperature T \[E=\frac{3}{2}kT\] where k = Boltzmann constant \[=1.38\times {{10}^{-23}}J/K\] For helium gas \[T=30+273=303K\] \[\therefore \] \[{{E}_{He}}=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 303\] \[=6.27\times {{10}^{-21}}J\] \[=\frac{6.27\times {{10}^{-21}}}{1.6\times {{10}^{-19}}}eV\] \[=3.9\times {{10}^{-2}}eV\] \[=0.039\text{ }eV\] The average kinetic energy of helium atom is less than 1 eV.
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