RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    A fan of moment of inertia\[0.6\text{ }kg-{{m}^{2}}\]is turned upto a working speed of 0.5 rev/s. The angular momentum of the fan is

    A)  \[0.3\pi \,kg-{{m}^{2}}/s\]

    B)  \[0.6\pi \,kg-{{m}^{2}}/s\]

    C)  \[\frac{0.03}{\pi }\,kg-{{m}^{2}}/s\]

    D)  \[\frac{0.6}{\pi }\,kg-{{m}^{2}}/s\]

    Correct Answer: B

    Solution :

     \[J=Im\] \[=1\times 2\pi n\] \[=0.06\times 27t\times 5\] \[=0.6TC\text{ }kg-{{m}^{2}}/\text{ }s\]


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