A) \[\sqrt{2}A\]
B) \[\frac{1}{\sqrt{2}}\,A\]
C) \[2A\]
D) \[\frac{1}{2}\,A\]
Correct Answer: A
Solution :
\[I=2\cos (\omega t+\theta )\] \[{{I}_{0}}=2\,A\] \[{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}=\frac{2}{\sqrt{2}}\] \[=\sqrt{2}A\]
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