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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    A given charge is situated at a certain distance from an electric dipole in the end on position experience a force F. If the distance of the charge is doubled, the force acting on the charge will be

    A)  zero          

    B)  \[F/2\]

    C)  \[F/4\]

    D)  \[F/8\]

    Correct Answer: D

    Solution :

     The intensity on axis line of dipole at any point \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{2p}{{{d}^{3}}}\] \[F=qE\] \[=\frac{2qp}{4\pi {{\varepsilon }_{0}}.{{d}^{3}}}\] Or \[F\propto \frac{1}{{{d}^{3}}}\] The force at distance 2d from centre \[F'={{\left( \frac{d}{2d} \right)}^{3}}F\] \[F'=\frac{F}{8}\]


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