A) 556 N
B) 3000 N
C) 843 N
D) 995 N
Correct Answer: C
Solution :
\[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] \[\Rightarrow \] \[T=4\,m{{n}^{2}}{{l}^{2}}\] \[=4\times 160\times {{10}^{-3}}\times {{(33)}^{2}}\times {{(1.1)}^{2}}\] \[=843N\]
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