A) \[Ke/2r\]
B) \[\frac{K{{e}^{2}}}{2r}\]
C) \[Ke/r\]
D) \[2Ke/4\]
Correct Answer: B
Solution :
\[KE=-\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}r}\] For hydrogen atom \[Z=1\]and \[\frac{1}{4\pi {{\varepsilon }_{0}}}=k\] \[KE=-\frac{k{{e}^{2}}}{2r}\]
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