RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    Half year of a radioactive element is 5 days. The time during which quantity remains 7/8 of initial mass will be

    A)  2, 5 days         

    B)  5 days

    C)  10 days          

    D)  15 days

    Correct Answer: D

    Solution :

     \[{{t}_{1/2}}=5\text{ }days\] \[N=\frac{{{N}_{0}}}{{{2}^{n}}}\] \[\frac{{{N}_{0}}}{8}=\frac{{{N}_{0}}}{{{2}^{n}}}\] \[n=3\] The total time\[=3\times 5=15\]days


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