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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The radius of the coil of a tangent galvanometer which has 10 turn is 0.1 m. The current required to produce a deflection of \[60{}^\circ \] is  

    A)  \[3A\]                

    B)  \[1.1A\]

    C)  \[2.1A\]

    D)  \[1.5A~\]

    Correct Answer: B

    Solution :

     \[I={{B}_{H}}\times \frac{2R\tan \theta }{N{{\mu }_{0}}}\] \[=4\times {{10}^{-5}}\times \frac{2\times 0.1\times \tan 60{}^\circ }{10\times 4\pi \times {{10}^{-7}}}\] \[=1.1A\]


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