A) II.
B) III and IV
C) I and IV
D) II and III
Correct Answer: A
Solution :
In\[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,,\]two types of hybridisation (\[s{{p}^{2}}\]and\[s{{p}^{3}}\]) are present.You need to login to perform this action.
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