RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    A lens is placed between a source of light and wall. It forms image of area\[{{A}_{1}}\]and\[{{A}_{2}}\]on the wall for its two different positions. The area of the source of light is

    A)  \[\frac{{{A}_{1}}+{{A}_{2}}}{2}\]

    B)  \[\sqrt{{{A}_{1}}{{A}_{2}}}\]

    C)  \[{{\left[ \frac{\sqrt{{{A}_{1}}}\,+\,\sqrt{{{A}_{2}}}}{2} \right]}^{2}}\]

    D)  \[{{\left[ \frac{1}{{{A}_{1}}}+\frac{1}{{{A}_{2}}} \right]}^{-1}}\]

    Correct Answer: B

    Solution :

     Area of light source for two conjugate states of lens \[=\sqrt{{{A}_{1}}{{A}_{2}}}\]


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