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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    A hospital uses an ultrasonic a scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is 1.7 km/s. The wavelength of sound in the tissue is close to

    A)  \[2\times {{10}^{-4}}m\]       

    B)  \[6\times {{10}^{-3}}m\]

    C)  \[2\times {{10}^{-3}}m\]       

    D)  \[4\times {{10}^{-4}}m\]

    Correct Answer: D

    Solution :

     \[\lambda =\frac{v}{n}=\frac{1.7\times {{10}^{3}}}{4.2\times {{10}^{6}}}=0.4\times {{10}^{-3}}\] \[=4\times {{10}^{-4}}m\]


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