A) \[v=\frac{1}{2R\sqrt{Gm}}\]
B) \[v=\sqrt{\frac{4Gm}{R}}\]
C) \[v=\sqrt{\frac{Gm}{2R}}\]
D) \[v=\frac{1}{2}\sqrt{\frac{Gm}{R}}\]
Correct Answer: D
Solution :
For circular motion \[\frac{m{{v}^{2}}}{R}=\frac{G{{m}^{2}}}{{{(2R)}^{2}}}\] \[\Rightarrow \] \[{{v}^{2}}=\frac{Gm}{4R}\] \[\Rightarrow \] \[v=\frac{1}{2}\sqrt{\frac{Gm}{R}}\]You need to login to perform this action.
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