A) \[{{v}_{0}}t+\frac{1}{3}b{{t}^{2}}\]
B) \[{{v}_{0}}t-\frac{1}{3}b{{t}^{2}}\]
C) \[{{v}_{0}}t+\frac{1}{6}b{{t}^{3}}\]
D) \[{{v}_{0}}t+\frac{1}{2}b{{t}^{3}}\]
Correct Answer: D
Solution :
\[\frac{{{d}^{2}}x}{d{{t}^{2}}}=bt\] The distance covered in time t by the particle \[s={{v}_{0}}t+\frac{1}{2}bt.{{t}^{2}}\] \[={{v}_{0}}t+\frac{1}{2}b{{t}^{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
