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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    An electric field is in the X- direction. If the work done to displace 0.2 C charge to 2m at an angle of \[60{}^\circ \]from X-axis along a straight line is 4 J, then the value of E will be

    A)  8 N/C            

    B)  4 N/C

    C)  \[\sqrt{3}\] N/C           

    D)  20 N/C

    Correct Answer: D

    Solution :

     \[W=Fd\,cos\theta =4J\] or          \[qEd\text{ }cos\text{ }\theta =4\] \[0.2\text{ }E\times 2\text{ }cos\text{ }60{}^\circ =4\] \[E=20N/C\]


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