A) 5-amino-2-heptenoic acid
B) p-amino-5-heptenoic acid
C) 5-amino-hex-2-ene carboxylic acid
D) 3-amino-5-heptenoic acid
Correct Answer: D
Solution :
\[\underset{3\text{ }-amino\text{ }-5-heptenoic\text{ }acid}{\mathop{\overset{7}{\mathop{C}}\,{{H}_{3}}-\overset{6}{\mathop{C}}\,H=\overset{5}{\mathop{C}}\,H-\overset{4}{\mathop{C}}\,{{H}_{2}}-\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \end{smallmatrix}}{\mathop{\overset{3}{\mathop{C}}\,H}}\,-\overset{2}{\mathop{C}}\,{{H}_{2}}-\overset{1}{\mathop{C}}\,OOH}}\,\]
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