A) internal energy increases
B) enthalpy increases
C) enthalpy becomes zero on decreasing
D) enthalpy remains unchanged
Correct Answer: D
Solution :
Isothermal process \[dT=0,\] \[\Delta E=0\] \[H=E+pV\] \[\Delta H=\Delta E+p.\Delta V\] where, \[\Delta H=\] change in enthalpy \[\Delta E=\] change in internal energy \[p=\]pressure \[\Delta V=\]change in volume during expansion of ideal gas If \[pV=nRT\] \[\Delta H=\Delta E+\Delta (nRT)\] \[\Delta H=\Delta E+nR.\Delta T\] \[\Delta T=0\] \[\Delta E=0\](Isothermal expansion) Hence, \[\Delta H=0\] During isothermal expansion, the enthalpy of ideal gas remains unchanged.
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