A) \[\pi /4\]
B) \[\pi /2\]
C) \[3\pi /4\]
D) \[5\pi /4\]
Correct Answer: C
Solution :
\[\because \]\[\overline{z}=iw=0\Rightarrow \overline{z}=-iw\] \[\Rightarrow \] \[z=iw\] \[\Rightarrow \] \[w=-iz\] and arg\[(zw)=\pi \] \[\Rightarrow \] \[\arg (-i{{z}^{2}})=\pi \] \[\Rightarrow \] \[\arg (-i)+\arg ({{z}^{2}})=\pi \] \[\Rightarrow \] \[-\frac{\pi }{2}+2\arg (z)=\pi \] \[[\because \arg (-i)=\pi /2]\] \[\Rightarrow \] \[2\arg (z)=\frac{3\pi }{2}\] \[\Rightarrow \] \[\arg (z)=\frac{3\pi }{4}\]
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