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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2007

  • question_answer
    A 100 V, AC source of frequency 500 Hz is connected to an L-C-R circuit with L = 8.1 mH, C = 12.5 \[\mu \] F, R = 10 \[\Omega \] all connected. What is the quality factor of circuit?

    A)  2.02           

    B)  2.5434                  

    C)  20.54                        

    D)  200.54          

    Correct Answer: B

    Solution :

     Q-factor    \[Q=\frac{\omega L}{R}=\frac{2\pi fL}{R}\] \[=\frac{2\times 3.14\times 500\times 8.1\times {{10}^{-3}}}{10}\] \[=2.5434\]


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