A) 1 : 1
B) 1 : 2
C) 2 : 1
D) 1 : 4
Correct Answer: A
Solution :
At depth d the gravity \[{{g}_{d}}=g\left( 1-\frac{d}{R} \right)\] at height\[h\] \[{{g}_{h}}=g\left( 1-\frac{2h}{R} \right)\] But \[d=2h\] \[\therefore \] \[{{g}_{d}}=g\left( 1-\frac{2h}{R} \right)\] \[{{g}_{d}}={{g}_{h}}\] or \[\frac{{{g}_{d}}}{{{g}_{h}}}=1:1\]
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