A) A
B) B
C) C
D) D
Correct Answer: A
Solution :
\[{{K}_{rot}}=\frac{1}{2}I{{\omega }^{2}}\] \[J=J\omega =\]constant In planetary motion, angular momentum remains conserved. At A the moment of inertia is least. So, angular speed is maximum. So, at point .A rotational kinetic energy is maximum.
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