RAJASTHAN ­ PET Rajasthan PET Solved Paper-2007

  • question_answer If BH = \[\frac{1}{\sqrt{3}}{{B}_{V}},\]find the angle of dip. (where symbols have at their usual meanings)

    A)  \[60{}^\circ \]             

    B)  \[30{}^\circ \]

    C)  \[45{}^\circ \]             

    D)  \[90{}^\circ \]

    Correct Answer: A

    Solution :

     Magnetic dip or magnetic inclination is given by       \[\tan \delta =\frac{{{B}_{V}}}{{{B}_{H}}}\] Given      \[{{B}_{H}}=\frac{1}{\sqrt{2}}{{B}_{V}}\] \[\frac{{{B}_{V}}}{{{B}_{H}}}=\sqrt{3}\] From Eqs. (i) and (ii), we get \[\tan \delta =\sqrt{3}\] \[\delta =60{}^\circ \]

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