A) \[y=3x+8\]
B) \[y=3x-8\]
C) \[y=3x+2\]
D) None of these
Correct Answer: D
Solution :
Let equation of the line which is parallel to \[y-3x-4=0\]is \[y=3x+k\] \[\because \] It is a tangent to the hyperbola \[\frac{{{x}^{2}}}{3}-\frac{{{y}^{2}}}{2}=1\] \[\therefore \] \[k=\sqrt{3{{(3)}^{2}}-2}\] \[(\because k=\sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}})\] \[=\sqrt{25}=5\] Hence, required equation of tangent is \[y=3x+5\]
You need to login to perform this action.
You will be redirected in
3 sec
