RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
    The unit vectors which is perpendicular to both vectors\[3\hat{i}+\hat{j}+2\hat{k}\]and\[2\hat{i}-2\hat{j}+4\hat{k},\]is

    A)  \[\frac{\hat{i}-\hat{j}-\hat{k}}{\sqrt{3}}\]

    B)  \[\frac{\hat{i}+\hat{j}+\hat{k}}{\sqrt{3}}\]

    C)  \[\frac{\hat{i}+\hat{j}-\hat{k}}{\sqrt{3}}\]        

    D)  None of these

    Correct Answer: A

    Solution :

     Let\[\overrightarrow{a}=3\hat{i}+\hat{j}+2\hat{k}\]and\[\overrightarrow{b}=2\hat{i}-2\hat{j}+4\hat{k}\] Now, \[\overrightarrow{a}\times \overrightarrow{b}=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    3 & 1 & 2  \\    2 & -2 & 4  \\ \end{matrix} \right|\] \[=\hat{i}(4+4)-\hat{j}(12-4)+\hat{k}(-6-2)\] \[=8\hat{i}-8\hat{j}-8\hat{k}\] \[\therefore \]Required unit vector \[=\frac{\overrightarrow{a}\times \overrightarrow{b}}{|\overrightarrow{a}\times \overrightarrow{b}|}\] \[=\frac{8(\hat{i}-\hat{j}-\hat{k})}{8\sqrt{{{1}^{2}}+{{1}^{2}}+{{1}^{2}}}}\] \[=\frac{\hat{i}-\hat{j}-\hat{k}}{\sqrt{3}}\]


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