RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
     The time period of two pendulums are T and 5T/4. They starts motion in SHM from equilibrium position. What will be the phase difference between them, after one complete oscillation by the big pendulum?

    A)  \[45{}^\circ \]            

    B)  \[90{}^\circ \]

    C)  \[60{}^\circ \]              

    D)  \[30{}^\circ \]

    Correct Answer: B

    Solution :

     When the large pendulum complete one oscillation, then the small pendulum. Complete\[\frac{5}{4}\]oscillation. Thus, the phase of small pendulum is about\[\frac{T}{4}\]s more than that of large pendulum. Hence, phase difference between them\[=\frac{\pi }{2}\]rad.


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