RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
    A voltmeter having a resistance of\[998\,\Omega \]is connected to a cell of emf 2 V and internal resistance\[2\,\Omega \]. The error in the measurement of emf will be

    A)  \[4\times {{10}^{-1}}V\]        

    B)  \[2\times {{10}^{-3}}V\]

    C)  \[4\times {{10}^{-3}}V\]       

    D)  \[2\times {{10}^{-1}}V\]

    Correct Answer: C

    Solution :

     Error in measurement = Actual value - Measured value Actual value \[=2V\] \[i=\frac{2}{998+2}=\frac{1}{500}A\] Since     \[E=V+ir\] \[\Rightarrow \] \[V=E-ir\] \[=2-\frac{1}{500}\times 2=\frac{998}{500}\] \[\therefore \] Measured value\[=\frac{998}{500}\] \[\Rightarrow \] Error\[=2-\frac{998}{500}=4\times {{10}^{-3}}V\]


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