A) current
B) voltage
C) power
D) frequency
Correct Answer: A
Solution :
For a step down transformer \[{{V}_{P}}>{{V}_{S}}\]but\[\frac{{{V}_{P}}}{{{V}_{S}}}=\frac{{{i}_{S}}}{{{i}_{P}}}\] \[\therefore \] \[{{i}_{S}}>{{i}_{P}}\] Current in the secondary coil is greater than the primary.
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