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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
    In the capacitor of capacitance C, charge Q and energy W is stored. If charge is increased upto 2Q, the energy stored will be

    A)  \[\frac{W}{4}\]              

    B)  \[\frac{W}{2}\]

    C)  2 W             

    D)  4 W

    Correct Answer: D

    Solution :

     From formula, \[W=\frac{{{Q}^{2}}}{2C}\] ?(i) \[W'=\frac{(2Q)}{2C}\] \[[\because Q'=2Q]\] \[\Rightarrow \] \[W'=4\frac{{{Q}^{2}}}{2C}\] \[\Rightarrow \] \[W'=4W\]             [From Eq. (i)]


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