RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
    8 g amount of a radioactive substance remains 0.5 g after 1 h. What is its half-life?

    A)  10 min          

    B)  15 min

    C)  30 min          

    D)  None of these

    Correct Answer: B

    Solution :

     \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[0.5=8{{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{5}{80}={{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{1}{16}={{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{n}}\] \[n=4\] \[T=n\times {{t}_{1/2}}\]


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