RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    An atom of mass M which is in the state of rest emits a photon of wavelength \[\lambda \] . As a result, the atom will deflect with the kinetic energy equal to (A is Planck's constant)

    A)  \[\frac{{{h}^{2}}}{M{{\lambda }^{2}}}\]

    B)  \[\frac{1}{2}\frac{{{h}^{2}}}{M{{\lambda }^{2}}}\]

    C)  \[\frac{h}{M\lambda }\]

    D)  \[\frac{1}{2}\frac{h}{M\lambda }\]   

    Correct Answer: B

    Solution :

     Momentum of photon, \[p=\frac{h}{\lambda }\] Kinetic energy of photon of mass M, K \[=\frac{{{p}^{2}}}{2M}\] or         \[K=\frac{{{h}^{2}}}{2M{{\lambda }^{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner